0,25x^2+8x-612=0

Solution for 0,25x^2+8x-612=0 equation:

0.25x^2+8x-612=0

a = 0.25; b = 8; c = -612;
Δ = b2-4ac
Δ = 82-4·0.25·(-612)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-26}{2*0.25}=\frac{-34}{0.5}
=-68
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+26}{2*0.25}=\frac{18}{0.5}
=36
$